In Fig. 3.2, the value of resistance R, such that the current from the supply will be 0.5 A, must be
The answer is :- 4
Total applied p.d. = 12 V, and total current =
0.5 A, therefore, totla resistance = 12 / 0.5 = 24
Resistance of parallell combination = 24 - 12 =
12
Hence
16R
16+R
= 12,
so 4R / (16+R) = 3
therefore 4R = 48 + 3R, and R = 48
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