If the circuit in Fig. 3.1 (as in the previous
problem), is connected across a 40V supply , the current in the
15 resistor will be
The answer is :- 2
P.D. across 15 resistor = 12 V,
so the current through 15 resistor = 12 / 15 = 0.8A.
Current through 10 resistor will be 12 / 10 = 1.2
A.
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