A double-sideband AM transmitter has a carrier frequency of 14.3MHz and the highest audio modulating frequency is 3kHz. The bandwidth will be
The answer is :- 3 Bandwidth = highest frequency-lowest frequency = (14.3 MHz + 3kHz) - (14.3 MHz - 3k Hz) = 6 kHz, i.e. from 14.297 MHz to 14.303 MHz The bandwidth will always be twice the highest audio modulating frequency.
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