A 20 F Capacitor is connected across an
8V, 1kHz supply. The current taken will be
approximately
The answer is :- 2 First we must calculate the reactance (ac resistance) of the capacitor, then calculate the current by Ohm's Law.
Taking an approximation of 2xPI as 6.28
Xc = 1 ÷ (6.28 x FREQ x CAP)
= 1 ÷ (6.28 x 1000 x 0.00002) = 1 ÷ 0.1256 = approximately 8 ohms
I = V / R = 8 / 8 = 1A
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