Resonance and its applications

Explanation of question 16

A parallel circuit is resonating at 2MHz, and has a Q factor of 200. The bandwidth will be

  1. 5kHz
  2. 10kHz
  3. 20kHz
  4. 125kHz

The answer is :- 2 

Bandwidth  = f / Q = 2,000,000 / 200 = 10,000 Hz = 10kHz

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