A parallel circuit is resonating at 2MHz, and has a Q factor of 200. The bandwidth will be
The answer is :- 2
Bandwidth = f / Q = 2,000,000 / 200 = 10,000 Hz = 10kHz
BACK |
page (tq1016ex) |
Some material Copyright John Bowyer G4KGS. |
Click here for important Copyright information |
Web Space provided by Hostroute.com Ltd |
Contact details |