A battery has an open-circuit voltage of 24V. When delivering a load current of 2A its terminal voltage falls to 20 V. The internal resistance of the battery is
The answer is :- 4
The difference between the open-circuit voltage and load voltage (24 V - 20 V = 4 V) will be across the internal resistance.
Current through internal resistance is 2 A,
therefore internal resistance = 4V / 2A = 2
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